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More stupid math

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Join Date: May 2005
Location: With Nick Danger
Posts: 17,798
More stupid math

And a stupid online puzzle game.

I like relaxing with little point and click puzzle games, but sometimes, they are not well designed, which spoils the relaxing.

To get the eight digit code to unlock the last gate I had to solve this set of equations:

e=a+d
h=c+7
d=h-2
g=a+c
b=c+3
f=c+b

I came up with a set of numbers, entered them, and it didn't work. I saw that there was a second solution (bad game design) but that didn't work either. DVD Talk Special Edition

Join Date: Feb 2001
Location: Berkeley, CA
Posts: 1,145
Re: More stupid math

Was one of your solutions this?:

Spoiler:

a=2
b=5
c=2
d=7
e=9
f=7
g=4
h=9 DVD Talk Legend

Join Date: May 2005
Location: With Nick Danger
Posts: 17,798
Re: More stupid math

I did solve the puzzle. It turned out to be one of those where you have to actually click on each clue before entering the solution will work. That wasn't it. DVD Talk Special Edition

Join Date: Feb 2001
Location: Berkeley, CA
Posts: 1,145
Re: More stupid math

I did solve the puzzle. It turned out to be one of those where you have to actually click on each clue before entering the solution will work. That wasn't it.
I think the puzzle has many many solutions. Pretty sloppy for a game. DVD Talk Legend

Join Date: Mar 2001
Location: Albuquerque
Posts: 22,348
Re: More stupid math

I don't come up with any solution.

Spoiler:

Assumptions:
Each of the numbers is a single digit, so that restricts the choices.
It's a direct substitution code, so each letter equals a unique number.

H= C+7, so C can only equal (0,1, or 2) and H will result in (7,8, or 9). So I laid out the equations.

D=H-2 and H=C+7 so D=C+5
F=C+B and B=C+3 so F=2C+3

C ===== (0,1,2)
H=C+7 = (7,8,9)
D=C+5 = (5,6,7)
B=C+3 = (3,4,5)
F=2C+3= (3,5,7)

If C=0, then B and F are duplicates, so that's out.
If C=2, then D and F are dupliates, so that's out.
So C=1.

It follows that
H=8
D=6
B=4
F=5

But
E= A+D
G=A+C

We know C=1 and D=6.
E=A+6 so A=(0,1,2,3) to be one digit. 1 is used for C, so A=(0,2,3)
G=A+1 so G=(1,3,4) 1 is used for C, 4 is used for B.
So G=3, and A=2.

E=A+6.
So E=8. But 8 is already taken by H.

The solution is inconsistent.

Last edited by Nick Danger; 06-22-18 at 05:12 PM. You may not post new threads
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