2nd grade math problem
#51
DVD Talk Hero
Re: 2nd grade math problem
Wrong! You're failing to take the gender wage gap into account. Maya should only get 82% of what her male counterparts get, so letting x = Male wage:
x + x + (.78)*x = 63
2.78 * x = 63
x = 63 / 2.78 = 22.66
.78 * x = 17.67
Since the units are pennies, which cannot be broken down into fractional parts, Maya takes the hit again (because she is the most likely to become pregnant and leave the job of cleaning the house, thus losing a significant amount of experience and job skill development), so Maya gets 17 cents, and Willie and Donald each get 23 cents.
x + x + (.78)*x = 63
2.78 * x = 63
x = 63 / 2.78 = 22.66
.78 * x = 17.67
Since the units are pennies, which cannot be broken down into fractional parts, Maya takes the hit again (because she is the most likely to become pregnant and leave the job of cleaning the house, thus losing a significant amount of experience and job skill development), so Maya gets 17 cents, and Willie and Donald each get 23 cents.
The quote is "finders keepers losers weepers." So the kid that found the coin should get the full coin. What is this Socialist equal distribution of the monies thing? Also, the dad (ie, the government) would take a cut to redistribute the wealth anyway, which is why you don't report "found" money to the feds.
#52
Re: 2nd grade math problem
Wrong! You're failing to take the gender wage gap into account. Maya should only get 82% of what her male counterparts get, so letting x = Male wage:
x + x + (.78)*x = 63
2.78 * x = 63
x = 63 / 2.78 = 22.66
.78 * x = 17.67
Since the units are pennies, which cannot be broken down into fractional parts, Maya takes the hit again (because she is the most likely to become pregnant and leave the job of cleaning the house, thus losing a significant amount of experience and job skill development), so Maya gets 17 cents, and Willie and Donald each get 23 cents.
x + x + (.78)*x = 63
2.78 * x = 63
x = 63 / 2.78 = 22.66
.78 * x = 17.67
Since the units are pennies, which cannot be broken down into fractional parts, Maya takes the hit again (because she is the most likely to become pregnant and leave the job of cleaning the house, thus losing a significant amount of experience and job skill development), so Maya gets 17 cents, and Willie and Donald each get 23 cents.

So, so true. This is the correct answer for the Snowflake generation.
Then, they should call CPS and turn their parents in for not giving them a big enough allowance... that's child mistreatment, endangerment, and cruelty. Let Dad rot in prison for 50 years... For shame!
#53
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Re: 2nd grade math problem
That’s what I was hoping for!


As for the coin issue ... who the hell actually uses currency, let alone coins? You just use the payment app of your choice and let it decide which friends owe what for the pizza delivery/Uber ride/legalized weed.
#55
Re: 2nd grade math problem
Take 28 from 48 and you are left with 20. Since the other 2 sides have to be the same length, add two of the same numbers together. If the sum is greater than 20, than choose a number lower than that number and get the sum. If the sum is less than 20 than use a number that is higher than that. Repeat until the sum equals 20. Trial and error method, but it will work.
#56
DVD Talk Hero
Re: 2nd grade math problem
Regarding shortcuts and recognizing easy nearby numbers:
I missed out on my chance to dazzle people with my math skills this week.
Someone in a meeting said "What's sixteen times eighteen?" I used to know my squares up to 25, but not anymore. If I still had that knowledge at my fingertips, I would have been able to tell them the answer instantly: 17^2 - 1. But, no, I had to wait for someone to do it on their computer.
I missed out on my chance to dazzle people with my math skills this week.

Someone in a meeting said "What's sixteen times eighteen?" I used to know my squares up to 25, but not anymore. If I still had that knowledge at my fingertips, I would have been able to tell them the answer instantly: 17^2 - 1. But, no, I had to wait for someone to do it on their computer.
#58
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Re: 2nd grade math problem
T=Total
R=T/2
G = T/6
Y=T/6
O=T/12
R=G + Y + O + B
R=G + Y + O + 6
substitute on the right side and solve for T
T=(12/5)R -72/5
substitute 2R for T
solve for R
R=36
G=12
Y=12
O=6
B=6
TotaL= 72
R=T/2
G = T/6
Y=T/6
O=T/12
R=G + Y + O + B
R=G + Y + O + 6
substitute on the right side and solve for T
T=(12/5)R -72/5
substitute 2R for T
solve for R
R=36
G=12
Y=12
O=6
B=6
TotaL= 72
#65
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Re: 2nd grade math problem
Without a pen and paper in front of me (and not reading Phil’s answer yet) ...
We’re working in 1/12ths ...
Half are red so ... 6/12
1/6th green so ... 2/12
1/6th yellow so ... 2/12
1/12 orange so ... 1/12
That gives us 11/12 spoken for, leaving 1/12th black.
1/12th = 6 black ones, so 6 x 12 gives us 72 jelly beans and pre-diabetes.
6 black, 6 orange, 12 yellow, 12 green, and 36 red.
Edit: agree with Trevor — his posts weren’t there when I started.
We’re working in 1/12ths ...
Half are red so ... 6/12
1/6th green so ... 2/12
1/6th yellow so ... 2/12
1/12 orange so ... 1/12
That gives us 11/12 spoken for, leaving 1/12th black.
1/12th = 6 black ones, so 6 x 12 gives us 72 jelly beans and pre-diabetes.
6 black, 6 orange, 12 yellow, 12 green, and 36 red.
Edit: agree with Trevor — his posts weren’t there when I started.

#68
DVD Talk Legend
Re: 2nd grade math problem
Without a pen and paper in front of me (and not reading Phil’s answer yet) ...
We’re working in 1/12ths ...
Half are red so ... 6/12
1/6th green so ... 2/12
1/6th yellow so ... 2/12
1/12 orange so ... 1/12
That gives us 11/12 spoken for, leaving 1/12th black.
1/12th = 6 black ones, so 6 x 12 gives us 72 jelly beans and pre-diabetes.
6 black, 6 orange, 12 yellow, 12 green, and 36 red.
Edit: agree with Trevor — his posts weren’t there when I started.
We’re working in 1/12ths ...
Half are red so ... 6/12
1/6th green so ... 2/12
1/6th yellow so ... 2/12
1/12 orange so ... 1/12
That gives us 11/12 spoken for, leaving 1/12th black.
1/12th = 6 black ones, so 6 x 12 gives us 72 jelly beans and pre-diabetes.
6 black, 6 orange, 12 yellow, 12 green, and 36 red.
Edit: agree with Trevor — his posts weren’t there when I started.

#69
Re: 2nd grade math problem
Algebra in 5th grade, but not really "algebra"? Sounds par for the course, with the touted core curriculum! Although giving credit, the problem does say "challenge", so that's justification enough for work which any 7th grader would do well to complete.
#70
DVD Talk Hero
Re: 2nd grade math problem
I converted all the fractions to a common denominator, twelfths, and added them up. They sum to 11/12, so 1/12 of the total must equal 6. It seemed obvious.
Fifth graders know about common denominators, so I say it's a fair question.
(I am also amused by the consecutive consonants in the word "twelfths". Take that, you Poles!)
Fifth graders know about common denominators, so I say it's a fair question.
(I am also amused by the consecutive consonants in the word "twelfths". Take that, you Poles!)
#71
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Re: 2nd grade math problem
Doesn’t seem excessive for fifth grade to me. Or for an Otter. 
Now ... expecting them to use algebraic equations might be a bit much ... but allowing them to figure it out first and then showing the connection to algebra is not.
Maybe we need to put it in terms Mabuse can relate to ...
Mabuse’s neighbors are all flying flags. 6 neighbors are flying Palestinian flags ...

Now ... expecting them to use algebraic equations might be a bit much ... but allowing them to figure it out first and then showing the connection to algebra is not.
Maybe we need to put it in terms Mabuse can relate to ...
Mabuse’s neighbors are all flying flags. 6 neighbors are flying Palestinian flags ...

#72
DVD Talk Legend
Re: 2nd grade math problem
So is that a fifth grade question?
If so, they should've done algebra, by now, even if they don't realize it.
We were taught 'word problems' where you had to express the problem using a variable.
They always had to start with something like:
Let X represent the number of apples in the basket.
I'd guess the latest we would've started doing that was grade 4.
I honestly don't remember what sort of math we were doing in grade 2. I'd think probably addition, subtraction, and times tables. I'm not sure about division.
Actually here's a list from PBS: Grade-by-Grade Learning Guide . Education | PBS Parents
If so, they should've done algebra, by now, even if they don't realize it.
We were taught 'word problems' where you had to express the problem using a variable.
They always had to start with something like:
Let X represent the number of apples in the basket.
I'd guess the latest we would've started doing that was grade 4.
I honestly don't remember what sort of math we were doing in grade 2. I'd think probably addition, subtraction, and times tables. I'm not sure about division.
Actually here's a list from PBS: Grade-by-Grade Learning Guide . Education | PBS Parents